GYN URI Essay Example | Topics and Well Written Essays - 750 words

GYN URI - Essay Example Getting off the Depo might decrease patient risk for OP in the future. Nexplanon is hormones- releasing birth control implement does not need daily taken or monthly injection placed under skin for long-acting methods http://www.nexplanon-usa.com/en/consumer/about-it/what-is-nexplanon/index.asp Furthermore, clinicians should educate the patient about LARCs.  Paragards are great in terms of length of efficacy. According to Hatcher et all (2007) in  Contraceptive Technology, women who experience irregular/heavy bleeding are significantly more likely to discontinue use of the IUD (p. 139), stating that 1 month follow up after insertion and use of NSAIDS can help reduce bleeding and rates of discontinuation.   So let us throw in the ACA and women access to contraceptive choices. These federal changes will include MAJOR changes in previously unavailable methods of birth control for the under or uninsured. I am going to refer to the ACNMs most recent survey, and now being heavily disseminated to media outlets, on womens perceptions of contraceptive choices. This is IMPORTANT for you to know, most women are unaware of the most effective methods, and many were previously not insured to receive LARC. http://ourmomentoftruth.midwife.org/OMOT-Contraception-and-Family-Planning. To learn MORE about ACA implantation. Depo-Provera use is not recommended for more than 2 years due to its effect on bone mineral density (BMD) loss in women. â€Å"On average women who used Depo have a BMD similar to non- users within two to three years after stopping the shots† (Flinn, 2011). Flinn indicates that the recovery of bone mass density is relative to the length of time a women used the Depo injections. Women who used Depo longer than a year were noted to take as long as 7 years before returning to their original BMD levels. Patient is at risk for osteoporosis due to age, race, and ethnicity. The clinician should make

The Fencing Problem Essay Example | Topics and Well Written Essays - 2500 words

The Fencing Problem - Essay Example Let us consider the square of sides 'a.' The Perimeter of square = Summation of all sides = a + a + a + a = 4 * a The Perimeter is given as 1000m 1000 = 4 * a a = 250m = each side of the square Area of square: A = a2 A = 2502 A = 62500m2 Hence if the shape the of the plot is square then the area that can be covered with the fencing of 1000m is 62500m2 Rectangle: Let the two sides of the rectangle be 'a' and 'b' Case I: Let side b = 2 * a i.e. the sides are in the ratio of 2:1 The Perimeter of rectangle = sum of all sides = 2 * (a + b) Here b = 2a P = 2 * (a + 2a) 1000 = 2 * (3 * a) a = 166.6m and b = 2 * 166.6 = 333.2m Area of rectangle A = a * b A = 166.6 * 333.2 A = 55511m2 Hence if the shape the of the plot is rectangular with sides in the ratio of 2:1 then the area that can be covered with the fencing of 1000m is 55511m2. Case II : Let the sides be in the ratio of 3:2 i.e. b = 1.5 * a P = 2 * (a + b) 1000 = 2 * ( a + 1.5 * a) 1000 = 5 * a a = 200m b = 1.5 * a = 300m Area of rectangle A = a * b A = 200 * 300 A = 60000m2 Hence if the shape the of the plot is rectangular with sides in the ratio of 3:2 then the area that can be covered with the fencing of 1000m is 60000m2. Equilateral Triangle: The equilateral triangle has three sides of the equal lengths. Here the three sides of triangle (a) will have length as: Total length of fencing/ 3 a = 1000/3 a = 333.3m The area of equilateral triangle is given by: A = * Base * Height A = * a * H The height of equilateral triangle is given by: sin60 = H/ side of triangle (a) H = sin60 * 333.3 (Angle 60o is the internal angle of the equilateral triangle) H = 289m A = * 333.3 * 289 A = 48098m2 Hence if the shape the of the...In this essay we shall first study the circle considering the perimeter as the circumference and from that finding the radius of the circle which than gives the area of the circle which can be covered with 1000m of the fence. Then we shall consider the square shape, for which first we shall find the sides of the square and then the area of the square. Thereafter we shall consider rectangle; in this we shall consider the sides of ratios 2:1 and 3:2, with the procedure same as that of the square. Then further we shall consider the triangle; first equilateral triangle is considered. For this the sides and the height of the triangle are found out and from that we get the area of the triangle. Then we have considered other two triangles; isosceles triangle and right angled triangle with the similar calculations. Thereafter various polygons are considered. Beginning with the pentagon its sides and the height are found and from that the area of the pentagon is found out. Similar approach is followed for the hexagon and the octagon. In the essay detailed calculations are shown for the various areas. The shape, which gives the maximum area, is also found and then the recommendations accordingly have been made. The calculations carried out are simple mathematical calculations. Pentagon is a type of the polygon with five sides. The sum of total angles inside the polygon is 3600.